Symptoms & Summary

Error 1505 Sql Server 2008 will appear and crash the current program window.
Your computer crashes frequently showing Error 1505 Sql Server 2008 whilst running the same program.
Your Windows runs slowly and mouse or keyboard input is sluggish.
Your computer will occasionally 'freeze' for a period of time.

Error 1505 Sql Server 2008 and other critical errors can occur when your Windows operating system becomes corrupted. Opening programs will be slower and response times will lag. When you have multiple applications running, you may experience crashes and freezes. There can be numerous causes of this error including excessive startup entries, registry errors, hardware/RAM decline, fragmented files, unnecessary or redundant program installations and so on.

Resolution

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Error 1505 Sql Server 2008

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The Duplicate Key Value Is ( Null )

This documentation is archived and is not being maintained. This documentation is archived and is not being maintained. MSSQLSERVER_1505 Other Versions SQL Server 2014 SQL Server 2012 Topic Status: Some information in this topic is preview and subject to change in future releases. Preview information describes new features or changes to existing features in Microsoft SQL Server 2016 Community Technology Preview 2 (CTP2). Details Product Name SQL cannot insert duplicate key row in object with unique index Server Event ID 1505 Event Source MSSQLSERVER Component SQLEngine Symbolic Name DUP_KEY Message Text CREATE UNIQUE INDEX terminated because a duplicate key was found for object name '%.*ls' and index name '%.*ls'. The duplicate key value is %ls. Explanation This error occurs when you attempt to create a unique index and more than one row in the table contains the specified duplicate value. A unique index is created when you create an index and specify the UNIQUE keyword, or when you create a UNIQUE constraint. The table cannot contain any rows that have duplicate values in the columns defined in the index or constraint. Consider the data in the following Employee table: LastName FirstName JobTitle HireDate Walters Rob Senior Tool Designer 2004-11-19 Brown Kevin Marketing Assistant NULL Brown Jo Design Engineer NULL Walters Rob Tool Designer 2001-08-09 A unique index can not be created on the column combinations LastName or LastName, FirstName because of duplicate values in the rows. Less obvious is the potential for a uniqueness violation in the HireDate column. For indexing purposes, NULL values compare as equal. Therefore, you cannot create a unique index or constraint if the key values are NULL in more than one row.

Error “The CREATE UNIQUE INDEX statement terminated because a duplicate key was found…” during GET LATEST in 2008 ★★★★★★★★★★★★★★★ CSSTFSBLOGFebruary sql server delete duplicate rows 18, 20092 0 0 0 Ladislau Szomoru (one of our

Dbcc Checktable

Escalation Engineers in Budapest) brings us today’s note about a problem some users are seeing in TFS

Find Duplicates In Sql

2008 Source Code Control. There is a specific situation emerging that is causing some customers to see the following error message on a GET LATEST: https://msdn.microsoft.com/en-us/library/cc280634.aspx The CREATE UNIQUE INDEX statement terminated because a duplicate key was found for the object name ‘dbo.#requestedVersions’ and the index name ‘IX_requestedVersions_ItemId’ At the same time the following event gets logged on the Team Foundation Server application tier machine in the Application Event Log: Detailed Message: TF14105: An exception occurred in the Team Foundation https://blogs.msdn.microsoft.com/dstfs/2009/02/18/error-the-create-unique-index-statement-terminated-because-a-duplicate-key-was-found-during-get-latest-in-2008/ Source Control System. Web Request Details Url: http://TFSERVER:8080/VersionControl/v1.0/repository.asmx [method: POST] User Agent: Team Foundation (devenv.exe, 9.0.30729.1) Headers: Content-Length=640&Content-Type=application%2fsoap%2bxml%3b+charset%3dutf-8&Accept-Encoding=gzip&Accept-Language=nb-NO&Expect=100-continue&Host=globe-dev2%3a8080&User-Agent=Team+Foundation+(devenv.exe%2c+9.0.30729.1)&X-TFS-Version=1.0.0.0&X-TFS-Session=6cc91dcd-1da6-4f69-a8f9-97e346098b39 Path: /VersionControl/v1.0/repository.asmx Local Request: False Host Address: xxx.xxx.xxx.xxx User: \ [authentication type: NTLM] Exception Message: The CREATE UNIQUE INDEX statement terminated because a duplicate key was found for the object name ‘dbo.#requestedVersions__________________________________________________________________________________________________000000001081' and the index name ‘IX_requestedVersions_ItemId'. The duplicate key value is (100). The statement has been terminated. (type SqlException) SQL Exception Class: 16 SQL Exception Number: 1505 SQL Exception Procedure: SQL Exception Line Number: 632 SQL Exception Server: SQL Exception State: 1 SQL Error(s): SQL Error[1]: System.Data.SqlClient.SqlError: The statement has been terminated. Class: 0 Number: 3621 Server: TFSERVER Source: .Net SqlClient Data Provider State: 0 Procedure: Line Number: 1 The error is caused by a data inconsistency due to which one or more version control items exist twice at the latest version. The Team Foundation Server product group has developed a SQL script which resolves some data inconsistency cases

1505, Level 16, State 1, Line 11The CREATE UNIQUE INDEX statement terminated because a duplicate key was found for the object name ‘%.*ls' http://www.sql-server-performance.com/2007/create-unique-index-terminated/ and the index name ‘%.*ls'. The duplicate key value is %ls. Severity level:16. Description:This error message appears when you try to create a unique index on column(s), for which https://www.experts-exchange.com/questions/23289824/How-to-find-and-remove-duplicate-keys-in-MSSQL-2005.html duplicate keys exist. Consequences:The T-SQL statement can be parsed, but causes the error at runtime. Resolution:Error of the Severity Level 16 are generated by the user and can be fixed duplicate key by the SQL Server user. The statement cannot be executed this way. The duplicate keys must be removed, or the index must be created as not unique index. Versions:All versions of SQL Server. Example(s):USE tempdb;IF OBJECT_ID(‘tempdb..#t') > 0DROP TABLE #tCREATE TABLE #t(c1 INT )INSERT INTO #t SELECT 1INSERT INTO #t SELECT 1 CREATE UNIQUE INDEX UI_t_c1 ON #t(c1) Remarks:In the the duplicate key above statement we try to create a unique index on the column c1. Because the key value 1 does exist more than once in that column, the creation of the index fails and the error is raised. ASK A QUESTION Tweet Array Errors No comments yet... Be the first to leave a reply! Leave a Reply Click here to cancel reply. Popular Latest Tags Setting up Transactional Replication in SQL Server 2008 R2. November 30, -0001 Backing Up a SQL Server Database Directly Onto a Remote Server November 30, -0001 Recovering a SQL Server Database from Suspect Mode November 30, -0001 SQL Server T-SQL Tuning - NOT IN and NOT Exists November 30, -0001 SQL Server T-SQL Tuning - Temp Tables, Table Variables and Union November 30, -0001 SQL Server Logical Reads – What do they really tell us? October 4, 2016 Physical Join Operators in SQL Server - Hash Operator September 21, 2016 Physical Join Operators in SQL Server - Merge Operator August 25, 2016 Techniques to Monitor SQL Server memory usage August 12, 2016 Recov

for Help Receive Real-Time Help Create a Freelance Project Hire for a Full Time Job Ways to Get Help Ask a Question Ask for Help Receive Real-Time Help Create a Freelance Project Hire for a Full Time Job Ways to Get Help Expand Search Submit Close Search Login Join Today Products BackProducts Gigs Live Careers Vendor Services Groups Website Testing Store Headlines Experts Exchange > Questions > How to find and remove duplicate keys in MSSQL 2005? Want to Advertise Here? Solved How to find and remove duplicate keys in MSSQL 2005? Posted on 2008-04-02 MS SQL Server 2 Verified Solutions 6 Comments 2,952 Views Last Modified: 2010-07-27 We have a database that will not complete tasks such as DBCC CHECKDB(DatabaseName, REPAIR_REBUILD). The errors is gives are: Msg 1505, Level 16, State 1, Line 1 The CREATE UNIQUE INDEX statement terminated because a duplicate key was found for the object name 'dbo.AllUserData' and the index name 'AllUserData_Url'. The duplicate key value is (ac2a5821-b785-4154-bf4c-9395e2d305df, 0x, 1, Departments/BSA/Lists/Workflow History, 473_.000, 0, 1, 0). The statement has been terminated. Msg 1505, Level 16, State 1, Line 1 The CREATE UNIQUE INDEX statement terminated because a duplicate key was found for the object name 'dbo.AllUserData' and the index name 'AllUserData_PK'. The duplicate key value is (350cd5ad-1f93-4646-a9f8-3392b3d4ab18, 473, 0, 1, 0). The statement has been terminated. I am not really a database person, but from what I can tell I need to find and fix/remove these duplicates. I tried issuing a REBUILD command on the mentioned indexes via the GUI (MS SQL Management Server Studio 2005) but got this error: An exception occurred while executing a Transact-SQL statement or batch. (Microsoft.SqlServer.ConnectionInfo) ------------------------------ Attempt to fetch logical page (1:233904) in database 5 failed. It belongs to allocation unit 72057594065911808 not to 72057594046382080. The statement has been terminated. (Microsoft SQL Server, Error: 605) How can I use the information in the errors to find the duplicate keys and remove them? 0 Question by:LakelandBank Facebook Twitter LinkedIn Google LVL 60 Best Solution bychapmandew this will find your duplicate records select keyfield, count(*) from alluser

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Windows Errors

A Windows error is an error that happens when an unexpected condition occurs or when a desired operation has failed. When you have an error in Windows, it may be critical and cause your programs to freeze and crash or it may be seemingly harmless yet annoying.

Blue Screen of Death

A stop error screen or bug check screen, commonly called a blue screen of death (also known as a BSoD, bluescreen), is caused by a fatal system error and is the error screen displayed by the Microsoft Windows family of operating systems upon encountering a critical error, of a non-recoverable nature, that causes the system to "crash".

Damaged DLLs

One of the biggest causes of DLL's becoming corrupt/damaged is the practice of constantly installing and uninstalling programs. This often means that DLL's will get overwritten by newer versions when a new program is installed, for example. This causes problems for those applications and programs that still need the old version to operate. Thus, the program begins to malfunction and crash.

Freezing Computer

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Virus Damage

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Computer Support

Error 1505 Sql Server 2008

The Duplicate Key Value Is ( Null )

Dbcc Checktable

Find Duplicates In Sql

Repair Instructions